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*DECK TAVGLM
SUBROUTINE TAVGLM(NB,SHIFT,BCHAN,PSI,BURN0,BURN1,IVECT,NSCH)
*
*-----------------------------------------------------------------------
*
*Purpose:
* Compute the burnup integration limits for a given channel.
*
*Copyright:
* Copyright (C) 2007 Ecole Polytechnique de Montreal
*
*Author(s):
* D.Rozon, M.Beaudet, D.Sekki, I. Trancart
*
*Parameters: input
* NB number of fuel bundles.
* SHIFT number of bundles to refuel (bundle-shift).
* PSI axial shape over each bundle.
* NSCH refuelling scheme of a given channel.
* BCHAN average exit burnup for a given channel.
* IVECT refuelling pattern vector for a given channel.
*
*Parameters: output
* BURN0 lower burnup integration limit.
* BURN1 upper burnup integration limit.
*
*Parameters: scratch
* DELT incremental burnup over each fuel bundle.
*
*-----------------------------------------------------------------------
*
*----
* SUBROUTINE ARGUMENTS
*----
INTEGER NB,SHIFT,NSCH,IVECT(NB),CHR(NB),AGLIM
REAL BURN0(NB),BURN1(NB),PSI(NB),BCHAN,DELT(NB)
*----
* LOCAL VARIABLES
*----
LOGICAL LAXSH
*----
* SCRATCH STORAGE ALLOCATION
*----
*----
* COMPUTE BURNUP LIMITS
*----
BURN0(:NB)=0.0
BURN1(:NB)=0.0
DELT(:NB)=0.0
LAXSH=.FALSE.
DO 10 IB=1,NB
DELT(IB)=SHIFT*BCHAN*PSI(IB)
IF(IVECT(IB).GT.IB)THEN
LAXSH=.TRUE.
ENDIF
10 CONTINUE
* Burnup attribution with axial Shuffling
IF(LAXSH)THEN
AGLIM=INT(NB/SHIFT)+1
CHR(:NB)=AGLIM
* Two loops on bundle cycles (IA) and nmake tesumber of bundles (IB)
DO 25 IA=0,AGLIM-1
DO 20 IB=1,NB
* Index ordering
IF (NSCH.LT.0) THEN
KK=NB-IB+1
KV=NB-IVECT(IB)+1
ELSE
KK=IB
KV=IVECT(IB)
ENDIF
* New fuel
IF(IVECT(IB).EQ.0)THEN
CHR(IB)=0
BURN0(KK)=0.
BURN1(KK)=DELT(KK)
ELSE
* Compute new burnup if previous bundle cycle done
IF(CHR(IVECT(IB)).EQ.(IA-1))THEN
CHR(IB)=IA
BURN0(KK)=BURN1(KV)
BURN1(KK)=DELT(KK)+BURN1(KV)
ENDIF
ENDIF
20 CONTINUE
25 CONTINUE
* Burnup attribution without axial Shuffling
* One loop on number of bundles (IB)
ELSE
* NEGATIVE DIRECTION
IF(NSCH.LT.0)THEN
DO 40 IB=1,NB
KK=NB-IB+1
KA=NB-IVECT(IB)+1
IF(IVECT(IB).LE.0)THEN
BURN0(KK)=0.
ELSE
BURN0(KK)=BURN1(KA)
ENDIF
BURN1(KK)=BURN0(KK)+DELT(KK)
40 CONTINUE
* POSITIVE DIRECTION
ELSE
DO 50 IB=1,NB
IF(IVECT(IB).LE.0)THEN
BURN0(IB)=0.
ELSE
BURN0(IB)=BURN1(IVECT(IB))
ENDIF
BURN1(IB)=BURN0(IB)+DELT(IB)
50 CONTINUE
ENDIF
ENDIF
*----
* SCRATCH STORAGE DEALLOCATION
*----
RETURN
END
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