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*DECK ALQUAR
SUBROUTINE ALQUAR(A,ROOTS)
*
*-----------------------------------------------------------------------
*
*Purpose:
* compute the roots of the real quartic polynomial defined as
* A(1)+A(2)*Z + ... + A(5)*Z**4.
* NOTE: It is assumed that A(5) is non-zero. No test is made here.
*
*Author(s): A. H. Morris, W. L. Davis, A. Miller, and R. L. Carmichael
*
*Parameters: input
* A polynomial coefficients
*
*Parameters: output
* ROOTS complex roots
*
*-----------------------------------------------------------------------
*
IMPLICIT NONE
*----
* SUBROUTINE ARGUMENTS
*----
DOUBLE PRECISION, INTENT(IN) :: A(5)
COMPLEX*16, INTENT(OUT) :: ROOTS(4)
*----
* LOCAL VARIABLES
*----
INTEGER :: I, J
INTEGER,DIMENSION(1) :: K
DOUBLE PRECISION :: B, B2, C, D, E, H, P, Q, R, T, WORK, U, V,
> V1, V2, X, XX(3), Y, BQ, CQ, DQ, AA, BB
COMPLEX*16 :: W, AAA, BBB, SQ1, TEST, SQRTM3
DOUBLE PRECISION,DIMENSION(4) :: TEMP
PARAMETER (SQRTM3=(0.0,1.73205080756888))
*
IF(A(1)==0.0) THEN
IF(A(2).EQ.0.0) THEN
CQ=A(4)/A(5)
DQ=A(3)/A(5)
AAA=CQ*CQ-4.0D0*DQ
AAA=SQRT(AAA)
ROOTS(1)=0.0
ROOTS(2)=0.0
ROOTS(3)=-0.5D0*(CQ+AAA)
ROOTS(4)=-0.5D0*(CQ-AAA)
ELSE
BQ=A(4)/A(5)
CQ=A(3)/A(5)
DQ=A(2)/A(5)
AA=(3.0D0*CQ-BQ**2)/3.0D0
BB=(2.0D0*BQ**3-9.0D0*BQ*CQ+27.0D0*DQ)/27.0D0
SQ1=BB**2/4.0D0+AA**3/27.0D0
TEST=BB/2.0D0-SQRT(SQ1)
IF(DBLE(TEST).EQ.0.0) THEN
AAA=0.0D0
ELSE IF(DBLE(TEST).GT.0.0) THEN
AAA=-(TEST)**(1.0D0/3.0D0)
ELSE
AAA=(-TEST)**(1.0D0/3.0D0)
ENDIF
TEST=BB/2.0D0+SQRT(SQ1)
IF(DBLE(TEST).EQ.0.0) THEN
BBB=0.0D0
ELSE IF(DBLE(TEST).GT.0.0) THEN
BBB=-(TEST)**(1.0D0/3.0D0)
ELSE
BBB=(-TEST)**(1.0D0/3.0D0)
ENDIF
ROOTS(1)=0.0
ROOTS(2)=AAA+BBB-BQ/3.0D0
ROOTS(3)=-(AAA+BBB)/2.0D0+(AAA-BBB)*SQRTM3/2.0D0-BQ/3.0D0
ROOTS(4)=-(AAA+BBB)/2.0D0-(AAA-BBB)*SQRTM3/2.0D0-BQ/3.0D0
ENDIF
RETURN
ENDIF
*----
* Solve a quartic equation
*----
B = A(4)/(4.0D0*A(5))
C = A(3)/A(5)
D = A(2)/A(5)
E = A(1)/A(5)
B2 = B*B
P = 0.5D0*(C - 6.0D0*B2)
Q = D - 2.0D0*B*(C - 4.0D0*B2)
R = B2*(C - 3.0D0*B2) - B*D + E
*----
* Solve the resolvent cubic equation. the cubic has at least one
* nonnegative real root. if W1, W2, W3 are the roots of the cubic
* then the roots of the original equation are
* ROOTS = -B + CSQRT(W1) + CSQRT(W2) + CSQRT(W3)
* where the signs of the square roots are chosen so
* that CSQRT(W1) * CSQRT(W2) * CSQRT(W3) = -Q/8.
*----
TEMP(1) = -Q*Q/64.0D0
TEMP(2) = 0.25D0*(P*P - R)
TEMP(3) = P
TEMP(4) = 1.0D0
BQ=TEMP(3)
CQ=TEMP(2)
DQ=TEMP(1)
AA=(3.0D0*CQ-BQ**2)/3.0D0
BB=(2.0D0*BQ**3-9.0D0*BQ*CQ+27.0D0*DQ)/27.0D0
SQ1=BB**2/4.0D0+AA**3/27.0D0
TEST=BB/2.0D0-SQRT(SQ1)
IF(DBLE(TEST).EQ.0.0) THEN
AAA=0.0D0
ELSE IF(DBLE(TEST).GT.0.0) THEN
AAA=-(TEST)**(1.0D0/3.0D0)
ELSE
AAA=(-TEST)**(1.0D0/3.0D0)
ENDIF
TEST=BB/2.0D0+SQRT(SQ1)
IF(DBLE(TEST).EQ.0.0) THEN
BBB=0.0D0
ELSE IF(DBLE(TEST).GT.0.0) THEN
BBB=-(TEST)**(1.0D0/3.0D0)
ELSE
BBB=(-TEST)**(1.0D0/3.0D0)
ENDIF
ROOTS(1)=AAA+BBB-BQ/3.0D0
ROOTS(2)=-(AAA+BBB)/2.0D0+(AAA-BBB)*SQRTM3/2.0D0-BQ/3.0D0
ROOTS(3)=-(AAA+BBB)/2.0D0-(AAA-BBB)*SQRTM3/2.0D0-BQ/3.0D0
IF(AIMAG(ROOTS(2)).NE.0.0D0) GO TO 60
*----
* The resolvent cubic has only real roots.
* Reorder the roots in increasing order.
*----
XX(1) = DBLE(ROOTS(1))
XX(2) = DBLE(ROOTS(2))
XX(3) = DBLE(ROOTS(3))
DO 25 J=2,3
X=XX(J)
DO 10 I=J-1,1,-1
IF(XX(I).LE.X) GOTO 20
XX(I+1)=XX(I)
10 CONTINUE
I=0
20 XX(I+1)=X
25 CONTINUE
U = 0.0D0
IF(XX(3).GT.0.0D0) U = SQRT(XX(3))
IF(XX(2).LE.0.0D0) GO TO 41
IF(XX(1).GE.0.0D0) GO TO 30
IF(ABS(XX(1)).GT.XX(2)) GO TO 40
XX(1) = 0.0D0
30 XX(1) = SQRT(XX(1))
XX(2) = SQRT(XX(2))
IF(Q.GT.0.0D0) XX(1) = -XX(1)
TEMP(1) = (( XX(1) + XX(2)) + U) - B
TEMP(2) = ((-XX(1) - XX(2)) + U) - B
TEMP(3) = (( XX(1) - XX(2)) - U) - B
TEMP(4) = ((-XX(1) + XX(2)) - U) - B
DO J=1,3
K=MINLOC(TEMP(J:))
IF(J.NE.K(1)) THEN
WORK = TEMP(J)
TEMP(J) = TEMP(K(1))
TEMP(K(1)) = WORK
ENDIF
ENDDO
IF(ABS(TEMP(1)).GE.0.1D0*ABS(TEMP(4))) GO TO 31
T = TEMP(2)*TEMP(3)*TEMP(4)
IF(T.NE.0.0D0) TEMP(1) = E/T
31 ROOTS(1) = CMPLX(TEMP(1), 0.0D0, KIND=KIND(ROOTS))
ROOTS(2) = CMPLX(TEMP(2), 0.0D0, KIND=KIND(ROOTS))
ROOTS(3) = CMPLX(TEMP(3), 0.0D0, KIND=KIND(ROOTS))
ROOTS(4) = CMPLX(TEMP(4), 0.0D0, KIND=KIND(ROOTS))
RETURN
40 V1 = SQRT(ABS(XX(1)))
V2 = 0.0D0
GO TO 50
41 V1 = SQRT(ABS(XX(1)))
V2 = SQRT(ABS(XX(2)))
IF(Q < 0.0D0) U = -U
50 X = -U - B
Y = V1 - V2
ROOTS(1) = CMPLX(X, Y, KIND=KIND(ROOTS))
ROOTS(2) = CMPLX(X,-Y, KIND=KIND(ROOTS))
X = U - B
Y = V1 + V2
ROOTS(3) = CMPLX(X, Y, KIND=KIND(ROOTS))
ROOTS(4) = CMPLX(X,-Y, KIND=KIND(ROOTS))
RETURN
*----
* The resolvent cubic has complex roots.
*----
60 T = DBLE(ROOTS(1))
X = 0.0D0
IF(T < 0.0D0) THEN
GO TO 61
ELSE IF(T.EQ.0.0D0) THEN
GO TO 70
ELSE
GO TO 62
ENDIF
61 H = ABS(DBLE(ROOTS(2))) + ABS(AIMAG(ROOTS(2)))
IF(ABS(T).LE.H) GO TO 70
GO TO 80
62 X = SQRT(T)
IF(Q.GT.0.0D0) X = -X
70 W = SQRT(ROOTS(2))
U = 2.0D0*DBLE(W)
V = 2.0D0*ABS(AIMAG(W))
T = X - B
XX(1) = T + U
XX(2) = T - U
IF(ABS(XX(1)).LE.ABS(XX(2))) GO TO 71
T = XX(1)
XX(1) = XX(2)
XX(2) = T
71 U = -X - B
H = U*U + V*V
IF(XX(1)*XX(1) < 0.01D0*MIN(XX(2)*XX(2),H)) XX(1) = E/(XX(2)*H)
ROOTS(1) = CMPLX(XX(1), 0.0D0, KIND=KIND(ROOTS))
ROOTS(2) = CMPLX(XX(2), 0.0D0, KIND=KIND(ROOTS))
ROOTS(3) = CMPLX(U, V, KIND=KIND(ROOTS))
ROOTS(4) = CMPLX(U,-V, KIND=KIND(ROOTS))
RETURN
80 V = SQRT(ABS(T))
ROOTS(1) = CMPLX(-B, V, KIND=KIND(ROOTS))
ROOTS(2) = CMPLX(-B,-V, KIND=KIND(ROOTS))
ROOTS(3) = ROOTS(1)
ROOTS(4) = ROOTS(2)
RETURN
END
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