*DECK TAVGLM SUBROUTINE TAVGLM(NB,SHIFT,BCHAN,PSI,BURN0,BURN1,IVECT,NSCH) * *----------------------------------------------------------------------- * *Purpose: * Compute the burnup integration limits for a given channel. * *Copyright: * Copyright (C) 2007 Ecole Polytechnique de Montreal * *Author(s): * D.Rozon, M.Beaudet, D.Sekki, I. Trancart * *Parameters: input * NB number of fuel bundles. * SHIFT number of bundles to refuel (bundle-shift). * PSI axial shape over each bundle. * NSCH refuelling scheme of a given channel. * BCHAN average exit burnup for a given channel. * IVECT refuelling pattern vector for a given channel. * *Parameters: output * BURN0 lower burnup integration limit. * BURN1 upper burnup integration limit. * *Parameters: scratch * DELT incremental burnup over each fuel bundle. * *----------------------------------------------------------------------- * *---- * SUBROUTINE ARGUMENTS *---- INTEGER NB,SHIFT,NSCH,IVECT(NB),CHR(NB),AGLIM REAL BURN0(NB),BURN1(NB),PSI(NB),BCHAN,DELT(NB) *---- * LOCAL VARIABLES *---- LOGICAL LAXSH *---- * SCRATCH STORAGE ALLOCATION *---- *---- * COMPUTE BURNUP LIMITS *---- BURN0(:NB)=0.0 BURN1(:NB)=0.0 DELT(:NB)=0.0 LAXSH=.FALSE. DO 10 IB=1,NB DELT(IB)=SHIFT*BCHAN*PSI(IB) IF(IVECT(IB).GT.IB)THEN LAXSH=.TRUE. ENDIF 10 CONTINUE * Burnup attribution with axial Shuffling IF(LAXSH)THEN AGLIM=INT(NB/SHIFT)+1 CHR(:NB)=AGLIM * Two loops on bundle cycles (IA) and nmake tesumber of bundles (IB) DO 25 IA=0,AGLIM-1 DO 20 IB=1,NB * Index ordering IF (NSCH.LT.0) THEN KK=NB-IB+1 KV=NB-IVECT(IB)+1 ELSE KK=IB KV=IVECT(IB) ENDIF * New fuel IF(IVECT(IB).EQ.0)THEN CHR(IB)=0 BURN0(KK)=0. BURN1(KK)=DELT(KK) ELSE * Compute new burnup if previous bundle cycle done IF(CHR(IVECT(IB)).EQ.(IA-1))THEN CHR(IB)=IA BURN0(KK)=BURN1(KV) BURN1(KK)=DELT(KK)+BURN1(KV) ENDIF ENDIF 20 CONTINUE 25 CONTINUE * Burnup attribution without axial Shuffling * One loop on number of bundles (IB) ELSE * NEGATIVE DIRECTION IF(NSCH.LT.0)THEN DO 40 IB=1,NB KK=NB-IB+1 KA=NB-IVECT(IB)+1 IF(IVECT(IB).LE.0)THEN BURN0(KK)=0. ELSE BURN0(KK)=BURN1(KA) ENDIF BURN1(KK)=BURN0(KK)+DELT(KK) 40 CONTINUE * POSITIVE DIRECTION ELSE DO 50 IB=1,NB IF(IVECT(IB).LE.0)THEN BURN0(IB)=0. ELSE BURN0(IB)=BURN1(IVECT(IB)) ENDIF BURN1(IB)=BURN0(IB)+DELT(IB) 50 CONTINUE ENDIF ENDIF *---- * SCRATCH STORAGE DEALLOCATION *---- RETURN END