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+*DECK LELCRN
+ FUNCTION LELCRN( CENTEC, RAYONC, X, Y)
+*
+*-----------------------------------------------------------------------
+*
+*Purpose:
+* Decide if the crown intersect a rectangular mesh.
+*
+*Copyright:
+* Copyright (C) 1990 Ecole Polytechnique de Montreal
+* This library is free software; you can redistribute it and/or
+* modify it under the terms of the GNU Lesser General Public
+* License as published by the Free Software Foundation; either
+* version 2.1 of the License, or (at your option) any later version
+*
+*Author(s): R. Roy
+*
+*Parameters: input
+* CENTEC coordinates of center.
+* RAYONC inner and outer radius**2 of the crown.
+* X X of the square.
+* Y Y of the square.
+*
+*Parameters: output
+* LELCRN checking flag: =.true. if interaction exists and
+* =.false. otherwise.
+*
+*-----------------------------------------------------------------------
+*
+ IMPLICIT NONE
+ LOGICAL LELCRN
+*
+ DOUBLE PRECISION CENTEC(2), RAYONC(2), X(2), Y(2), R
+ INTEGER NBEXT, NBINT, IX, IY
+*
+ NBEXT=0
+ NBINT=0
+ DO 20 IX=1, 2
+ DO 10 IY=1, 2
+ R= (X(IX)-CENTEC(1))*(X(IX)-CENTEC(1))
+ > + (Y(IY)-CENTEC(2))*(Y(IY)-CENTEC(2))
+ IF( R.LE.RAYONC(1) ) NBINT= NBINT+1
+ IF( R.GE.RAYONC(2) ) NBEXT= NBEXT+1
+ 10 CONTINUE
+ 20 CONTINUE
+ IF( NBINT.EQ.4 )THEN
+*
+* RECTANGLE IS CONTAINED INSIDE THE INTERNAL RADIUS
+ LELCRN=.FALSE.
+ ELSEIF( NBEXT.EQ.4 )THEN
+ IF( Y(1).LT.CENTEC(2).AND.CENTEC(2).LT.Y(2) )THEN
+ IF( CENTEC(1).LT.X(1) )THEN
+ LELCRN= (X(1)-CENTEC(1))*(X(1)-CENTEC(1)).LT.RAYONC(2)
+ ELSEIF( X(2).LT.CENTEC(1) )THEN
+ LELCRN= (X(2)-CENTEC(1))*(X(2)-CENTEC(1)).LT.RAYONC(2)
+ ELSE
+ LELCRN=.TRUE.
+ ENDIF
+ ELSEIF( X(1).LT.CENTEC(1).AND.CENTEC(1).LT.X(2) )THEN
+ IF( CENTEC(2).LT.Y(1) )THEN
+ LELCRN= (Y(1)-CENTEC(2))*(Y(1)-CENTEC(2)).LT.RAYONC(2)
+ ELSEIF( Y(2).LT.CENTEC(2) )THEN
+ LELCRN= (Y(2)-CENTEC(2))*(Y(2)-CENTEC(2)).LT.RAYONC(2)
+ ELSE
+ LELCRN=.TRUE.
+ ENDIF
+ ELSE
+ LELCRN=.FALSE.
+ ENDIF
+ ELSE
+ LELCRN=.TRUE.
+ ENDIF
+*
+ RETURN
+ END